Question:
Cuprous ion is colourless while cupric ion is coloured because:
Cuprous ion is colourless while cupric ion is coloured because:
Show Hint
A complete d-orbital configuration prevents d-d transitions, making the ion colourless.
Updated On: Apr 2, 2025
- Both have half-filled p- and d-orbitals.
- Cuprous ion has an incomplete d-orbital and cupric ion has a complete d-orbital.
- Both have unpaired electrons in the d-orbitals.
- Cuprous ion has a complete d-orbital and cupric ion has an incomplete d-orbital.
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding electronic configurations.
- \( Cu^+ \) has a complete 3d\(^{10}\) configuration (no d-d transitions, thus colourless).
- \( Cu^{2+} \) has a 3d\(^9\) configuration (allows d-d transitions, thus coloured).
- \( Cu^+ \) has a complete 3d\(^{10}\) configuration (no d-d transitions, thus colourless).
- \( Cu^{2+} \) has a 3d\(^9\) configuration (allows d-d transitions, thus coloured).
Was this answer helpful?
0
0
Top Questions on Thermodynamics
- Given are statements for certain thermodynamic variables: \begin{itemize} \item[(A)] Internal energy, volume \( V \), and mass \( M \) are extensive variables. \item[(B)] Pressure \( P \), temperature \( T \), and density \( \rho \) are intensive variables. \item[(C)] Volume \( V \), temperature \( T \), and density \( \rho \) are intensive variables. \item[(D)] Mass \( M \), temperature \( T \), and internal energy are extensive variables. \end{itemize} Choose the correct answer from the options given below:
- JEE Main - 2025
- Physics
- Thermodynamics
- For a diatomic gas, if \( \gamma_1 = \frac{C_P}{C_V} \) for rigid molecules and \( \gamma_2 = \frac{C_P}{C_V} \) for another diatomic molecules, but also having vibrational modes. Then, which one of the following options is correct? (where \( C_P \) and \( C_V \) are specific heats of the gas at constant pressure and volume)
- JEE Main - 2025
- Physics
- Thermodynamics
- Match List - I with List - II. List - I (Partial Derivatives) \(and\) List - II (Thermodynamic Quantity)
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- Thermodynamics
- A container of fixed volume contains a gas at 27°C. To double the pressure of the gas, the temperature of the gas should be raised to °C.
- JEE Main - 2025
- Physics
- Thermodynamics
- The work done in an adiabatic change in an ideal gas depends upon:
- JEE Main - 2025
- Physics
- Thermodynamics
View More Questions
Questions Asked in VITEEE exam
- Let \( f(x) \) be defined as: \[f(x) = \begin{cases} 3 - x, & x<-3 \\ 6, & -3 \leq x \leq 3 \\ 3 + x, & x>3 \end{cases}\]
Let \( \alpha \) be the number of points of discontinuity of \( f(x) \) and \( \beta \) be the number of points where \( f(x) \) is not differentiable. Then, \( \alpha + \beta \) is:- VITEEE - 2024
- Matrices
- The area bounded by \( y - 1 = |x| \) and \( y + 1 = |x| \) is: (a) \( \frac{1}{2} \)
- VITEEE - 2024
- Conic sections
- The length of the perpendicular from the point \( (1, -2, 5) \) on the line passing through \( (1, 2, 4) \) and parallel to the line given by \( x + y - z = 0 \) and \( x - 2y + 3z - 5 = 0 \) is:
- VITEEE - 2024
- Differential equations
- If \( A \) and \( B \) are the two real values of \( k \) for which the system of equations \( x + 2y + z = 1 \), \( x + 3y + 4z = k \), \( x + 5y + 10z = k^2 \) is consistent, then \( A + B = \): (a) 3
- VITEEE - 2024
- Binomial theorem
- A and B are independent events of a random experiment if and only if:
- VITEEE - 2024
- Relations and functions
View More Questions