Question:
\(\int \frac{cos x - sin x}{1 + sin2x} dx\) is equal to:
\(\int \frac{cos x - sin x}{1 + sin2x} dx\) is equal to:
Updated On: May 18, 2024
- \(\frac{1}{sinx + cosx}c\), where C is a constant.
- \(\frac{- 1}{sinx + cosx}c\), where C is a constant.
- \(\frac{1}{cos x - sinx}c\), where C is a constant.
- \(\frac{2}{sinx + cosx}c\), where C is a constant.
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac{- 1}{sinx + cosx}c\), where C is a constant.
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