Question:

Correct order of 1st ionisation potential (IP) among following elements Be, B, C, N, O is

Updated On: May 5, 2024
  • B < Be < C < O < N
  • B < Be < C < N < 0
  • Be < B < C < N < O
  • Be < B < C < O < N
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The Correct Option is A

Solution and Explanation

The amount of energy required to remove an electron from the outermost orbit of a gaseous atom is known as ionisation potential. Elements having
half-filled or completely filled' orbitals are more stable than partially filled orbitals.
In a period from left to right ionisation potential decreases as the atomic number increases. The given elements (Be, B, C, N, O) are present in II period as
$\xrightarrow{\begin {array}
\ Be \ \ \ \ \ \ \ \ B \ \\
\ Ionisation
\end {array} \begin {array}
\ \ \ C \ \ \ \ \ N \ \ \ \ \ O \\
\ \ potential \ \ increases \\
\end {array} }$
But in case of Be and B, Be has higher ionisation potential due to stable configuration
So, the correct order of increasing ionisation potential will be
B < Be < C < 0 < N
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Concepts Used:

Haloalkanes and Haloarenes - Classification

Classification of Haloalkanes and Haloarenes are as follows:

Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:

These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;

  • Monohaloalkane
  • Dihaloalkane
  • Trihaloalkane

Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)

This class includes:

  • Alkyl halides or haloalkanes (R—X)
  • Allylic halides
  • Benzylic halides

Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond

This class includes:

  • Vinylic halides
  • Aryl halides