Corona loss increases with:
Step 1: Corona loss occurs in high-voltage transmission lines where air ionization around the conductor causes power dissipation.
Step 2: The corona power loss per unit length can be estimated using the formula: \[ P_c = f (V - V_c)^2 \frac{1}{\delta r} \] where \( f \) is the supply frequency, \( V \) is the operating voltage, \( V_c \) is the critical disruptive voltage, \( \delta \) is the air density factor, and \( r \) is the conductor radius.
Step 3: From the formula, corona loss increases when: - Frequency (\( f \)) increases: The power loss is directly proportional to frequency. - Conductor radius (\( r \)) decreases: Smaller conductors increase the electric field intensity, resulting in higher ionization and corona effect.
Step 4: Therefore, the correct answer is a decrease in conductor size and an increase in supply frequency.
The circuit shown in figure is
For the circuit shown in the figure, the delay of the bubbled NAND gate is 5 ns and that of the counter is assumed to be zero. If the clock (Clk) frequency is 12 MHz, then the counter behaves as a ________.
The circuit shown in the figure can be used as a ________.
If diode cut-in voltage is 0.6 V. The diode status are