Question:

Considering the reaction sequence given below, the correct statement(s) is(are)
Treating P with conc. NH4OH solution followed by acidification gives Q.
 

Updated On: Jul 10, 2024
  • $P$ can be reduced to a primary alcohol using $NaBH _4$.
  • Treating $P$ with conc. $NH _4 OH$ solution followed by acidification gives $Q$.
  • Treating $Q$ with a solution of $NaNO _2$ in aq. $HCl$ liberates $N _2$.
  • $P$ is more acidic than $CH _3 CH _2 COOH$.
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The Correct Option is B, C, D

Solution and Explanation

(B) Treating P with conc. NH4OH solution followed by acidification gives Q.  
(C) Treating Q with a solution of NaNO2 in aq. HCl liberates N2. 
(D) P is more acidic than CH3CH2COOH.
Treating P with conc. NH4OH solution followed by acidification gives Q. 

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Concepts Used:

Aldehydes, Ketones and Carboxylic Acids - Chemical Reactions

Chemical Reactions of Aldehydes and Ketones:

Nucleophilic Addition Reactions
Nucleophilic Addition Reactions
Tollens’ test
Tollens’ Test
Fehling’s test
Fehling’s Test
Aldol condensation
Aldol Condensation
  • Cross aldol condensation
Cross aldol condensation
Cross Aldol Condensation
Cannizzaro reaction
Cannizzaro Reaction
Electrophilic Substitution Reaction
Electrophilic Substitution Reaction

Read Also: Aldehydes, Ketones, and Carboxylic Acids

Fischer Esterification
Fischer Esterification
Decarboxylation
Decarboxylation
Halogenation
Halogenation

Read More: Chemistry Named Reactions