Question:

Consider the system of two linear equations as follows: 3x + 21y + p = 0; and qx + ry – 7 = 0, where p , q, and r are real numbers.
Which of the following statements DEFINITELY CONTRADICTS the fact that the lines represented by the two equations are coinciding?

Updated On: Dec 10, 2024
  • p and q must have opposite signs
  • The smallest among p, q, and r is r
  • The largest among p, q, and r is q
  • r and q must have same signs
  • p cannot be 0
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Analyze the conditions for coinciding lines. For the lines 3x + 2y + p = 0 and qx + qy − 7 = 0 to coincide, the coefficients of x, y, and the constants must be proportional:

$\frac{3}{q} = \frac{2}{q} = \frac{p}{-7}$

Step 2: Test each statement.

  • Option 1: p and q must have opposite signs. This contradicts the proportionality condition, as proportional coefficients cannot have opposite signs.
  • Option 2: The smallest among p, q, and r is r. This does not contradict the proportionality condition.
  • Option 3: The largest among p, q, and r is q. This does not contradict the proportionality condition.
  • Option 4: r and q must have the same signs. This is consistent with the proportionality condition.
  • Option 5: p cannot be 0. This does not contradict the proportionality condition, as p can be nonzero.

Answer: Option 1.

Was this answer helpful?
0
1

Questions Asked in XAT exam

View More Questions