Question:

Consider the junction diode as ideal. The value of current flowing through $AB$ is :

Updated On: Apr 20, 2025

$10^{-2} A$
$10^{-1} A$
$10^{-3} A$
$ 0 A$

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The Correct Option is A

Solution and Explanation

Diode Forward Bias Calculation

In the given problem, the diode is in forward bias, and we need to calculate the current $i$ using Ohm's Law.

Ohm's law is given by:

$i = \frac{\Delta V}{R}$,

where:

$\Delta V$ is the voltage across the resistor (the difference between the voltage across the diode and the supply voltage),
R is the resistance of the resistor.

Substituting the given values:

$i = \frac{\Delta V}{R} = \frac{4 - (-6)}{1 \times 10^3}$

Now, calculating the voltage difference:

$i = \frac{4 + 6}{1 \times 10^3} = \frac{10}{10^3}$

Finally, we get:

$i = 10^{-2} \, A$

Conclusion:

The current flowing through the diode when it is in forward bias is 10^-2 A.

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Consider the junction diode as ideal. The value of current flowing through \(AB\) is :