Step 1: Analyze Statement (A) Statement (A) is written as: \[ \int_a^b \frac{d}{dx} \left( f(x) \right) dx = \frac{d}{dx} \int_a^b f(x) dx \] We know the Leibniz Rule for differentiating an integral: \[ \frac{d}{dx} \int_a^b f(x) \, dx = f(b) - f(a) \] So, the correct expression should be: \[ \int_a^b \frac{d}{dx} \left( f(x) \right) dx = f(b) - f(a) \] Thus, the statement (A) is incorrect, as it implies the derivative inside the integral equals the derivative of the integral over the limits.
Step 2: Analyze Statement (B) Statement (B) is written as: \[ \frac{d}{dx} \left( \int f(x) \, dx \right) = f(x) + C \] The derivative of an indefinite integral \( \int f(x) \, dx \) is simply \( f(x) \). The constant of integration \( C \) is irrelevant when differentiating. Therefore, the correct expression is: \[ \frac{d}{dx} \left( \int f(x) \, dx \right) = f(x) \] Statement (B) incorrectly adds the constant \( C \), which is unnecessary.
Step 3: Final Conclusion Both statements (A) and (B) are false, hence the correct answer is: \[ \boxed{\text{Both (A) and (B) are false.}} \]
Let \( f : (0, \infty) \to \mathbb{R} \) be a twice differentiable function. If for some \( a \neq 0 \), } \[ \int_0^a f(x) \, dx = f(a), \quad f(1) = 1, \quad f(16) = \frac{1}{8}, \quad \text{then } 16 - f^{-1}\left( \frac{1}{16} \right) \text{ is equal to:}\]
X, Y are oxoacids of phosphorous. The number of P – OH bonds in X, Y respectively is: