Question

Compound A formed in the following reaction reacts with B gives the product C. Find out A and B.\[ \text{CH}_3 - \text{C} \equiv \text{CH} + \text{Na} \xrightarrow{} \text{A}\xrightarrow{B} \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_2 - \text{CH}_2 + \text{NaBr}(C)\]

• A.

  

• B.

  

• C.

  

• D.

  

Answer 1

The Correct Option is C

The given reaction suggests that sodium acetylide reacts with an alkyl halide to yield the final product. Here, compound A is formed as sodium acetylide:

CH₃ – C ≡ CH + Na → CH₃ – C ≡ CNa

Then, it reacts with compound B (1-bromopropane):

CH₃ – C ≡ CNa + CH₃CH₂CH₂Br → CH₃ – C ≡ C – CH₂CH₂CH₃ + NaBr