Step 1: Reflexive Property.
For the relation \( R \) to be reflexive, it must contain the pair \( (a,a) \) for every element \( a \in I \). Here, the relation does not contain \( (4,4), (5,5), (6,6), (7,7) \), so \( R \) is not reflexive.
Step 2: Symmetric Property.
For the relation to be symmetric, if \( (a,b) \) is in the relation, then \( (b,a) \) must also be in the relation. Here, \( (4,5) \) and \( (5,4) \) are present, and similarly for the other pairs, making \( R \) symmetric.
Step 3: Transitive Property.
For the relation to be transitive, if \( (a,b) \) and \( (b,c) \) are in the relation, then \( (a,c) \) must also be in the relation. However, \( (4,5) \) and \( (5,4) \) should imply \( (4,4) \), but \( (4,4) \) is not in the relation, so \( R \) is not transitive.
Step 4: Antisymmetric Property.
For the relation to be antisymmetric, if \( (a,b) \) and \( (b,a) \) are in the relation, then \( a = b \). In this case, both \( (4,5) \) and \( (5,4) \) are present, but \( 4 \neq 5 \) and \( 5 \neq 4 \), so \( R \) is not antisymmetric.
Step 5: Conclusion.
The relation does not have the transitive property, so the correct answer is (1) A, C and D only.
Let \( A = \{-3, -2, -1, 0, 1, 2, 3\} \). A relation \( R \) is defined such that \( xRy \) if \( y = \max(x, 1) \). The number of elements required to make it reflexive is \( l \), the number of elements required to make it symmetric is \( m \), and the number of elements in the relation \( R \) is \( n \). Then the value of \( l + m + n \) is equal to:
The speed-density relation on a one-way, single lane road is shown in the figure, where speed \( u \) is in km/hour and density \( k \) is in vehicles/km. The maximum flow (in vehicles/hour) on this road is
The following circuit generates the same output as?