To solve the problem, we need to find the number of people who like both tea and coffee using the principle of inclusion-exclusion.
- Total People: 50
- Number liking tea (T): 30
- Number liking coffee (C): 25
- Number liking neither: 10
- Use the formula for union:
\[
|T \cup C| = |T| + |C| - |T \cap C|
\]
- People liking tea or coffee or both = total - neither
Total people = 50
Neither = 10 → People liking tea or coffee or both = 50 - 10 = 40
Tea (T) = 30
Coffee (C) = 25
\[ |T \cup C| = 40 = 30 + 25 - |T \cap C| \] \[ |T \cap C| = 30 + 25 - 40 = 15 \]
The number of people who like both tea and coffee is 15.
Let \( A = \{-3, -2, -1, 0, 1, 2, 3\} \). A relation \( R \) is defined such that \( xRy \) if \( y = \max(x, 1) \). The number of elements required to make it reflexive is \( l \), the number of elements required to make it symmetric is \( m \), and the number of elements in the relation \( R \) is \( n \). Then the value of \( l + m + n \) is equal to:
The speed-density relation on a one-way, single lane road is shown in the figure, where speed \( u \) is in km/hour and density \( k \) is in vehicles/km. The maximum flow (in vehicles/hour) on this road is

Fill in the blank with the correct option.
The teacher believed that the student’s sudden lack of interest in class was an ..........., as he had always been enthusiastic and attentive.
What comes next in the series?
\(2, 6, 12, 20, 30, \ ?\)