Step 1: Identify Molecule \(Y\) - In the reaction \(\text{X} + \text{O}_2 \rightarrow \text{Cu}_2\text{O} + \text{SO}_2\), the gas produced is \(\text{SO}_2\). - Therefore, \(Y\) is \(\text{SO}_2\).
Step 2: Structure of \(\text{SO}_2\) - \(\text{SO}_2\) has a bent (or V-shaped) structure due to the presence of a lone pair on the sulfur atom and two S–O double bonds. - The bond angle is approximately \(119^\circ\), which makes it an \emph{angular} molecule. Hence, the shape of molecule \(Y\) (\(\text{SO}_2\)) is (angular).
Consider the following (unbalanced) reactions:
\[ \text{BF}_3 + \text{NaH} \xrightarrow{450\,\mathrm{K}} X + \text{NaF} \]
\[ X + \text{H}_2\text{O} \rightarrow Y + \text{H}_2 \uparrow \]
The correct statements about \(X\) and \(Y\) are:
Arrange the following in the correct order of their boiling points:
The number of -OH groups present in the structures of bithionol, terpineol, and chloroxylenol is respectively:
Conversion of X to Y in the given reaction corresponds to:
Reaction of conversion of Y to Z in the given reaction corresponds to:
Arrange the following in the increasing order of pKa values.