Step 1: Identify Molecule \(Y\) - In the reaction \(\text{X} + \text{O}_2 \rightarrow \text{Cu}_2\text{O} + \text{SO}_2\), the gas produced is \(\text{SO}_2\). - Therefore, \(Y\) is \(\text{SO}_2\).
Step 2: Structure of \(\text{SO}_2\) - \(\text{SO}_2\) has a bent (or V-shaped) structure due to the presence of a lone pair on the sulfur atom and two S–O double bonds. - The bond angle is approximately \(119^\circ\), which makes it an \emph{angular} molecule. Hence, the shape of molecule \(Y\) (\(\text{SO}_2\)) is (angular).
Identify the correct orders against the property mentioned:
A. H$_2$O $>$ NH$_3$ $>$ CHCl$_3$ - dipole moment
B. XeF$_4$ $>$ XeO$_3$ $>$ XeF$_2$ - number of lone pairs on central atom
C. O–H $>$ C–H $>$ N–O - bond length
D. N$_2$>O$_2$>H$_2$ - bond enthalpy
Choose the correct answer from the options given below:

