Question:
Consider the following reaction.
The correct structure of \( Y \) is
Consider the following reaction.
The correct structure of \( Y \) is
The correct structure of \( Y \) is
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Lithium aluminium hydride (LiAlH\(_4\)) reduces amides to amines, removing the carbonyl group.
Updated On: Jan 28, 2026
- PhCH\(_2\)NHCOPh
- Ph–CH\(_2\)NCH\(_2\)Ph
- PhNH\(_2\)CH\(_2\)Ph
- PhCH\(_3\)
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The Correct Option is D
Solution and Explanation
Step 1: Reaction with acyl chloride.
The first step involves the reaction of \( \text{CH}_3\text{NH}_2 \) (methylamine) with phenylacetyl chloride (PhCOCl), which results in the formation of an amide: \[ \text{CH}_3\text{NH}_2 + \text{PhCOCl} \rightarrow \text{PhCH}_2\text{NHCOPh}. \] Step 2: Reduction with LiAlH\(_4\).
The second step involves the reduction of the amide with lithium aluminium hydride (LiAlH\(_4\)), which reduces the amide group to an amine, resulting in the formation of \( \text{PhCH}_3 \) (toluene). Final Answer: \[ \boxed{\text{PhCH}_3}. \]
The first step involves the reaction of \( \text{CH}_3\text{NH}_2 \) (methylamine) with phenylacetyl chloride (PhCOCl), which results in the formation of an amide: \[ \text{CH}_3\text{NH}_2 + \text{PhCOCl} \rightarrow \text{PhCH}_2\text{NHCOPh}. \] Step 2: Reduction with LiAlH\(_4\).
The second step involves the reduction of the amide with lithium aluminium hydride (LiAlH\(_4\)), which reduces the amide group to an amine, resulting in the formation of \( \text{PhCH}_3 \) (toluene). Final Answer: \[ \boxed{\text{PhCH}_3}. \]
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