Step 1: From inequality (2).
\[
3p + 2q < 6
\]
Since \(p, q\) are positive integers, smallest values are at least 1.
If \(p=1\):
\[
3(1) + 2q < 6 \Rightarrow 3 + 2q < 6 \Rightarrow 2q < 3 \Rightarrow q < 1.5
\]
Thus, \(q = 1\).
Step 2: Check inequality (1).
\[
p^2 - 4q < 4
\]
Substitute \(p=1, q=1\):
\[
1^2 - 4(1) = 1 - 4 = -3 < 4 \text{(satisfied).}
\]
Step 3: Compute \(p+q\).
\[
p+q = 1+1 = 2
\]
\[
\boxed{2}
\]
P and Q play chess frequently against each other. Of these matches, P has won 80% of the matches, drawn 15% of the matches, and lost 5% of the matches.
If they play 3 more matches, what is the probability of P winning exactly 2 of these 3 matches?