Question

Consider the following alphabet series: A B C D E F G H I J K L M N O P Q R S T U V W X Y Z If the second half of the given alphabet series is written in reverse order, which letter will be seventh to the right of the twelfth letter from the left end?

• A. R
• B. S
• C. U
• D. T

Hint:

When dealing with alphabet series, reversing half of the sequence and counting positions can help identify the correct answer.

Answer 1

The Correct Option is C

Step 1: Reverse the second half of the alphabet.
The second half of the alphabet is: \[ M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z \] Reversing this gives: \[ Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M \]

Step 2: Construct the new series.
The modified series becomes: \[ A, B, C, D, E, F, G, H, I, J, K, L, Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M \]

Step 3: Find the twelfth letter and the seventh letter to the right of it.
The twelfth letter from the left end is \( L \). Counting seven letters to the right of \( L \), we get: \[ Z, Y, X, W, V, U, T \] Thus, the seventh letter to the right of \( L \) is \( U \). Therefore, the correct answer is 3. U.