Question:

Consider the above reaction, the product 'X' and 'Y' respectively are 

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Aldol products always follow this sequence: Aldol (Addition) $\xrightarrow{-H_2O}$ Enone (Condensation). The double bond in the final product is always between $\alpha$ and $\beta$ carbons.
Updated On: Jan 12, 2026
  • A
  • B
  • C
  • D
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The Correct Option is A

Solution and Explanation

Step 1: This is an Aldol Condensation of cyclopentanone.
Step 2: In the presence of dil. \(NaOH\), one molecule of cyclopentanone forms an enolate and attacks another molecule to form the \(\beta\)-hydroxy ketone (Product 'X').
Step 3: Upon heating (often in acidic medium for final dehydration), a molecule of water is lost to form the \(\alpha,\beta\)-unsaturated ketone (Product 'Y').
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