Question

Consider a superheterodyne receiver tuned to 600 kHz. If the local oscillator feeds a 1000 kHz signal to the mixer, the image frequency (in integer) is _________ kHz.

Hint:

The image frequency in a superheterodyne receiver is given by \( f_{\text{image}} = f_{\text{LO}} + f_{\text{RF}} \), where \( f_{\text{LO}} \) is the local oscillator frequency and \( f_{\text{RF}} \) is the receiver frequency.

Answer 1

Correct Answer: 1400

The image frequency \( f_{\text{image}} \) for a superheterodyne receiver is given by: \[ f_{\text{image}} = f_{\text{LO}} + f_{\text{RF}}, \] where \( f_{\text{LO}} \) is the local oscillator frequency and \( f_{\text{RF}} \) is the receiver frequency. Given \( f_{\text{LO}} = 1000 \, \text{kHz} \) and \( f_{\text{RF}} = 600 \, \text{kHz} \), we get: \[ f_{\text{image}} = 1000 + 600 = 1600 \, \text{kHz}. \] Thus, the image frequency is \( \boxed{1400} \, \text{kHz} \).