Question:

Consider a one-dimensional harmonic oscillator of angular frequency \( \omega \). If \( N \) identical particles occupy the energy levels of this oscillator at zero temperature, which of the following statement(s) about their ground state energy \( E_0 \) is (are) correct?

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For fermions, the ground state energy is affected by the Pauli exclusion principle, while for bosons, the energy depends on Bose-Einstein condensation.
Updated On: Nov 18, 2025
  • If the particles are electrons, \( E_0 = \frac{13}{2} \hbar \omega \)
  • If the particles are protons, \( E_0 = \frac{25}{2} \hbar \omega \)
  • If the particles are spin-less fermions, \( E_0 = \frac{25}{2} \hbar \omega \)
  • If the particles are bosons, \( E_0 = \frac{5}{2} \hbar \omega \)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the ground state energy.
For a quantum harmonic oscillator, the ground state energy for spin-less fermions is determined by the Pauli exclusion principle. The total energy depends on the number of available states. For fermions, the energy of the system is given by \( E_0 = \frac{25}{2} \hbar \omega \).
Step 2: Conclusion.
Thus, the correct answer is option (C).
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