Question

The moment of inertia of a thin ring about its diameter is:

• A. \(MR^2\)
• B. \(\frac{1}{2}MR^2\)
• C. \(\frac{1}{4}MR^2\)
• D. \(2MR^2\)

Hint:

Ring: \(I_{\text{center}} = MR^2\), diameter = half of it.

Answer 1

The Correct Option is B

For a ring, \(I_{\text{diameter}} = \frac{1}{2}MR^2\) using perpendicular axis theorem.