Question

A projectile is launched with speed 50 m/s at \(60^\circ\) to the horizontal. The time of flight is (\(g=10\ \text{m/s}^2\)):

• A. 5 s
• B. 10 s
• C. 8.66 s
• D. \(5\sqrt{3}\) s

Hint:

Time of flight depends on vertical component of velocity.

Answer 1

The Correct Option is D

\[ T=\frac{2u\sin\theta}{g} =\frac{2\times50\times\sin60^\circ}{10} =\frac{100\times\sqrt{3}/2}{10}=5\sqrt{3}\ \text{s} \]