Question

Consider a conical region of height h and base radius R with its vertex at the origin. Let the outward normal to its base be along the positive z-axis, as shown in the figure. A uniform magnetic field, \(\overrightarrow{B}=B_0\hat{z}\) exists everywhere. Then the magnetic flux through the base (\(\Phi_b\)) and that through the curved surface of the cone (\(\Phi_c\)) are

• A. \(\Phi_b=B_0\pi R^2;\Phi_c=0\)
• B. \(\Phi_b=-\frac{1}{2}B_0\pi R^2;\Phi_c=\frac{1}{2}B_0\pi R^2\)
• C. \(\Phi_b=0;\Phi_c=-B_0\pi R^2\)
• D. \(\Phi_b=B_0\pi R^2;\Phi_c=-B_0\pi R^2\)

Answer 1

The Correct Option is D

The correct answer is (D) : \(\Phi_b=0;\Phi_c=-B_0\pi R^2\)