To solve this problem, we need to consider the modified Maxwell's equations that account for the possibility of magnetic monopoles. The divergence of the magnetic field in this case is given by:
\(ββ.\vec{π΅} = \mu_0 \rho_m\)
where \(\mu_0\) is the permeability of vacuum and \(\rho_m\) is the magnetic charge density.
According to the modified Maxwell's equations, the curl of the electric field \((\vec{E})\) in the presence of a magnetic current density \((\vec{J}_m)\) is given by:
\(ββ Γ \vec{πΈ} = -\frac{β\vec{B}}{βt} - \mu_0 \vec{J}_m\)
This equation indicates that the change in the magnetic field over time and the magnetic current density both contribute to the curl of the electric field.
Now, let us match this derived expression with the provided options:
Thus, the correct answer is:
\(-\mu_0 \vec{J}_m - \frac{β\vec{B}}{βt}\)


At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/mΒ³, which is dimensionally incorrect for a spectral density. The correct unit J/(mΒ³Β·Hz) or JΒ·s/mΒ³ is used here for the solution.)