Step 1: Derive the truth table for \( F(X, Y, Z) \).
The given \( F(X, Y, Z) = \Sigma(3, 5, 6, 7) \) corresponds to minterms where the function evaluates to 1. These minterms are:
\[
3 (011), 5 (101), 6 (110), 7 (111).
\]
Step 2: Convert to product-of-maxterms.
Maxterms where \( F(X, Y, Z) = 0 \) are \( 0 (000), 1 (001), 2 (010), 4 (100) \).
Thus, the complement of \( F(X, Y, Z) \) is given by \( \Pi(0, 1, 2, 4) \). This makes Option (1) TRUE.
Step 3: Simplify the Boolean expression.
Using minterms, the Boolean expression can be simplified as:
\[
F(X, Y, Z) = XY + YZ + XZ.
\]
This makes Option (2) TRUE.
Step 4: Check independence of \( X \) or \( Y \).
The function depends on all three variables (\( X, Y, Z \)), as flipping any variable changes the output.
Thus, \( F(X, Y, Z) \) is NOT independent of \( X \) or \( Y \), making Options (3) and (4) FALSE.
Final Answer:
\[
\boxed{(1), (2)}
\]