Connecting link between glycolysis and Krebs' cycle before pyruvate entering Krebs' cycle is changed to
- oxaloacetate
- PEP
- pyruvate
- acetyl
The Correct Option is D
Solution and Explanation
The correct answer is D: Acetyl
Glycolysis is the 1st step of cellular respiration and it is a common process for aerobic and anaerobic respiration. Glycolysis occurs in absence of oxygen. The product of glycolysis is pyruvate which oxidizes into Acetyl CoA. The oxidized product then enters into mitochondria and takes part in the Krebs Cycle.
Important Notes on the above concepts:
- Glycolysis is the metabolic pathway in which, glucose C₆H₁₂O₆ converts into pyruvate, CH₃COCOO⁻, and a hydrogen ion, H⁺.
- The energy released in this process is used in ATP and NADH formation.
- The final process of this process is pyruvic acid.
- The Krebs cycle is a series of chemical reactions used by all aerobic organisms to release stored energy through the oxidation of acetyl-CoA derived from carbohydrates, fats, and proteins.
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Concepts Used:
Respiration in Plants
Respiration in plants is a process that entails the production of energy in plants. This process can simply be described as the intake of Oxygen and the release of Carbon Dioxide as an outcome of the oxidation of complex organic compounds. Though plants do not have any specific organ to balance the process of respiration, their stems, roots, and leaves do this work at a very low rate than other living beings. The process of respiration is very crucial for the plants to sustain the growth of the plant tissues.
This process can be stated as-
\[C_6H_{12}O_6 + 6O_2 → 6CO_2 + 6H_2O + \text{Energy}\]