Question:
Concentrated H\(_2\)SO\(_4\) reacts with PCl\(_5\) to produce
Concentrated H\(_2\)SO\(_4\) reacts with PCl\(_5\) to produce
Show Hint
When sulfuric acid reacts with PCl\(_5\), sulfuryl chloride (SO\(_2\)Cl\(_2\)) and phosphorus oxychloride (POCl\(_3\)) are typically formed.
Updated On: Jan 30, 2026
- HClO\(_2\)
- SO\(_2\)Cl\(_2\)
- SOCl\(_2\)
- HClO\(_4\)
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understanding the reaction.
Concentrated sulfuric acid (H\(_2\)SO\(_4\)) reacts with phosphorus pentachloride (PCl\(_5\)) to produce sulfuryl chloride (SO\(_2\)Cl\(_2\)) and phosphorus oxychloride (POCl\(_3\)).
Step 2: Analyzing the options.
(A) HClO\(_2\): This compound is not formed in the reaction with PCl\(_5\).
(B) SO\(_2\)Cl\(_2\): Correct — This is sulfuryl chloride, the product of the reaction.
(C) SOCl\(_2\): This is thionyl chloride, but it is not the product of this reaction.
(D) HClO\(_4\): This is perchloric acid, which is not formed in this reaction.
Step 3: Conclusion.
The correct answer is (B) SO\(_2\)Cl\(_2\), which is formed in the reaction between concentrated H\(_2\)SO\(_4\) and PCl\(_5\).
Concentrated sulfuric acid (H\(_2\)SO\(_4\)) reacts with phosphorus pentachloride (PCl\(_5\)) to produce sulfuryl chloride (SO\(_2\)Cl\(_2\)) and phosphorus oxychloride (POCl\(_3\)).
Step 2: Analyzing the options.
(A) HClO\(_2\): This compound is not formed in the reaction with PCl\(_5\).
(B) SO\(_2\)Cl\(_2\): Correct — This is sulfuryl chloride, the product of the reaction.
(C) SOCl\(_2\): This is thionyl chloride, but it is not the product of this reaction.
(D) HClO\(_4\): This is perchloric acid, which is not formed in this reaction.
Step 3: Conclusion.
The correct answer is (B) SO\(_2\)Cl\(_2\), which is formed in the reaction between concentrated H\(_2\)SO\(_4\) and PCl\(_5\).
Was this answer helpful?
0
0
Top Questions on Inorganic chemistry
- Consider the following statements:
[(A)] \(\mathrm{KMnO_4}\) is diamagnetic while \(\mathrm{K_2MnO_4}\) is paramagnetic.
[(B)] Manganate ion contains \(\mathrm{Mn^{6+}}\) while permanganate ion contains \(\mathrm{Mn^{7+}}\).
[(C)] \(\mathrm{Mn^{2+}}\) ion on reaction with \(\mathrm{S_2O_8^{2-}}\) ions gives manganate ion.
[(D)] Both \(\mathrm{MnO_4^-}\) and \(\mathrm{MnO_4^{2-}}\) are tetrahedral.
Correct statements are:- JEE Main - 2026
- Chemistry
- Inorganic chemistry
- Statement-I : \(\mathrm{KMnO_4}\) is a good reducing agent.
Statement-II : \(\mathrm{KMnO_4}\) reduces nitrite, oxalate and iodide ions.- JEE Main - 2026
- Chemistry
- Inorganic chemistry
Given below are two statements:
Statement I: All the pairs of molecules \((\mathrm{PbO}, \mathrm{PbO_2}); (\mathrm{SnO}, \mathrm{SnO_2})\) and \((\mathrm{GeO}, \mathrm{GeO_2})\) contain amphoteric oxides.
Statement II: \(\mathrm{AlCl_3}, \mathrm{BH_3}, \mathrm{BeH_2}\) and \(\mathrm{NO_2}\) all have incomplete octet.
In the light of the above statements, choose the correct option.- JEE Main - 2026
- Chemistry
- Inorganic chemistry
- In the following reaction, \[ {MnO4^{2-} \xrightarrow{H^+} \, ?} \] Manganate ion undergoes disproportionation to form:
- JEE Main - 2026
- Chemistry
- Inorganic chemistry
- The compound(s) with P–H bond(s) is(are):
- JEE Advanced - 2025
- Chemistry
- Inorganic chemistry
View More Questions
Questions Asked in MHT CET exam
- If $ f(x) = 2x^2 - 3x + 5 $, find $ f(3) $.
- MHT CET - 2025
- Functions
- Evaluate the definite integral: \( \int_{-2}^{2} |x^2 - x - 2| \, dx \)
- MHT CET - 2025
- Definite Integral
- There are 6 boys and 4 girls. Arrange their seating arrangement on a round table such that 2 boys and 1 girl can't sit together.
- MHT CET - 2025
- permutations and combinations
- Given the equation: \[ 81 \sin^2 x + 81 \cos^2 x = 30 \] Find the value of \( x \).
- MHT CET - 2025
- Trigonometric Identities
- Evaluate the integral: \[ \int \frac{1}{\sin^2 2x \cdot \cos^2 2x} \, dx \]
- MHT CET - 2025
- Trigonometric Identities
View More Questions