1 | 2 | 3 | 4 |
5 | 6 | 7 | 8 |
9 | 10 |
To solve the problem, we need to follow these logical steps based on the conditions provided:
Upon evaluating row sums, the least sum (11) is correctly computed, falling within the expected range of (4, 4). Therefore, the third row has the smallest sum satisfying the conditions.
Both I and II
Neither I nor II
Using the given conditions, we can determine the following placements:
Thus, both statements (I) and (II) are true.
Neither I nor II
Both I and II
Based on the conditions:
As a result, neither statement I nor II must be true, making the correct option 2. Neither I nor II.
Based on the given constraints, we can deduce the following:
(a) 1 and 10:
• Must be in the same row or column.
• Due to increasing rows and decreasing columns, they must be placed in opposite corners.
• Possible placements:
– 1 in Row 1, Column 1 and 10 in Row 4, Column 1.
– 1 in Row 4, Column 4 and 10 in Row 1, Column 4.
(b) 4 and 6:
• Must be in the same row.
• Cannot be in Row 1 or Row 4 (due to 1 and 10).
• So, they must be in either Row 2 or Row 3.
(c) 2, 3, 7, and 8:
• Their placements are restricted by the placements of 1, 10, 4, and 6.
(d) Uncertain Slots:
• Due to these constraints, we cannot definitively determine the placement of num-
bers in the following two slots:
– The slot in Row 4, Column 2 or Column 3: This slot cannot be filled with 1, 2, 3, 4, 6, 7, 8, or 10.
– The other slot in Row 4: This slot also cannot be filled with 1, 2, 3, 4, 6, 7, 8, or 10.
Therefore, the answer to the question ”For how many slots in the grid, placement of
numbers CANNOT be determined with certainty?” is 2.
Column 1 | Column 2 | Column 3 | Column 4 |
---|---|---|---|
Row 1 | 1 | 2 | 3 |
Row 2 | 4 | 5 | 6 |
Row 3 | 7 | 8 | 9 |
Row 4 | 10 |
Note: Other valid configurations may exist, but the number of uncertain slots remains
the same.
Based on the given constraints, we can deduce the following:
(a) 1 and 10:
• Must be in the same row or column.
• Due to increasing rows and decreasing columns, they must be placed in opposite corners.
• Possible placements:
– 1 in Row 1, Column 1 and 10 in Row 4, Column 1.
– 1 in Row 4, Column 4 and 10 in Row 1, Column 4.
(b) 4 and 6:
• Must be in the same row.
• Cannot be in Row 1 or Row 4 (due to 1 and 10).
• So, they must be in either Row 2 or Row 3.
(c) 2, 3, 7, and 8:
• Their placements are restricted by the placements of 1, 10, 4, and 6.
Determining the Sum of Column 4:
Considering the constraints and the possible placements, we can deduce that:
- Column 4 must contain the numbers 1, 9, and 10.
Therefore, the sum of the numbers in Column 4 is:
1 + 9 + 10 = 20
Thus, the final answer is 20.
The following histogram represents: