Compound A undergoes the following reaction to form B and C:
\[
\text{KNO}_3 + \text{KOH} \to \text{Black coloured solid} (A) \xrightarrow{\text{heated}} \text{Green coloured solid B} + \text{Pink solution + A} (\text{C decolorised by Fe}^{2+})
\]
Identify A, B, and C respectively
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In redox reactions involving manganese compounds, the oxidation states of manganese change. \( \text{MnO}_2 \) is reduced to form \( \text{KMnO}_4 \), and the intermediate compound is \( \text{K}_2\text{MnO}_4 \).
\( \text{MnO}_2, \text{KMnO}_4 \) and \( \text{K}_2\text{MnO}_4 \)
\( \text{MnO}_2, \text{K}_2\text{MnO}_4 \) and \( \text{KMnO}_4 \)
\( \text{KMnO}_4, \text{MnO}_2 \) and \( \text{K}_2\text{MnO}_4 \)
\( \text{KMnO}_4, \text{K}_2\text{MnO}_4 \) and \( \text{MnO}_2 \)
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The Correct Option isB
Solution and Explanation
In this reaction, potassium nitrate reacts with potassium hydroxide, resulting in the formation of manganese dioxide (\( \text{MnO}_2 \)) as the black solid. Upon heating, this black solid reacts further to form potassium permanganate (\( \text{KMnO}_4 \)) and potassium manganate (\( \text{K}_2\text{MnO}_4 \)).
The correct sequence of compounds is:
A: \( \text{MnO}_2 \),
B: \( \text{K}_2\text{MnO}_4 \),
C: \( \text{KMnO}_4 \).
Thus, the correct answer is (b).
