Complete the following nuclear equation: \( \^{30}_{15}Si + ? \rightarrow ? + 1e^0 \)
To complete the given nuclear equation, we follow these steps:
The initial equation is: \(\ ^{30}_{15}Si + ? \rightarrow ? + 1e^0 \)
In nuclear reactions, the sum of the atomic numbers (subscripts) on both sides of the equation must be equal, as must the mass numbers (superscripts).
1. Analyze the given equation:
2. Applying conservation of charge and mass number:
3. Identify the missing components: If a beta decay process is occurring, a neutron is converted to a proton, releasing the beta particle. Therefore, expect the atomic number on the reaction product side to increase by 1 to 16 (phosphorus, P) while the mass number remains at 30.
Thus the balanced equation is: \(\ ^{30}_{15}Si \rightarrow \ ^{30}_{16}P + 1e^0 \)
4. Therefore, the completed equation is consistent with option \(( 0 + 1e^0 )\) as a notation adjustment, aligning with our balanced equation where the resulting component supports charge and mass conservation.
In conclusion, the completion involves recognition of the process results and maintaining the balance using the chosen option.
Mass Defect and Energy Released in the Fission of \( ^{235}_{92}\text{U} \)
When a neutron collides with \( ^{235}_{92}\text{U} \), the nucleus gives \( ^{140}_{54}\text{Xe} \) and \( ^{94}_{38}\text{Sr} \) as fission products, and two neutrons are ejected. Calculate the mass defect and the energy released (in MeV) in the process.
Given: