Complete the following nuclear equation: \( \^{30}_{15}Si + ? \rightarrow ? + 1e^0 \)
To complete the given nuclear equation, we follow these steps:
The initial equation is: \(\ ^{30}_{15}Si + ? \rightarrow ? + 1e^0 \)
In nuclear reactions, the sum of the atomic numbers (subscripts) on both sides of the equation must be equal, as must the mass numbers (superscripts).
1. Analyze the given equation:
2. Applying conservation of charge and mass number:
3. Identify the missing components: If a beta decay process is occurring, a neutron is converted to a proton, releasing the beta particle. Therefore, expect the atomic number on the reaction product side to increase by 1 to 16 (phosphorus, P) while the mass number remains at 30.
Thus the balanced equation is: \(\ ^{30}_{15}Si \rightarrow \ ^{30}_{16}P + 1e^0 \)
4. Therefore, the completed equation is consistent with option \(( 0 + 1e^0 )\) as a notation adjustment, aligning with our balanced equation where the resulting component supports charge and mass conservation.
In conclusion, the completion involves recognition of the process results and maintaining the balance using the chosen option.
Match the LIST-I with LIST-II
LIST-I (Type of decay in Radioactivity) | LIST-II (Reason for stability) | ||
---|---|---|---|
A. | Alpha decay | III. | Nucleus is mostly heavier than Pb (Z=82) |
B. | Beta negative decay | IV. | Nucleus has too many neutrons relative to the number of protons |
C. | Gamma decay | I. | Nucleus has excess energy in an excited state |
D. | Positron Emission | II. | Nucleus has too many protons relative to the number of neutrons |
Choose the correct answer from the options given below:
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The density of the copper ($^{64}Cu$) nucleus is greater than that of the carbon ($^{12}C$) nucleus.
Reason (R): The nucleus of mass number A has a radius proportional to $A^{1/3}$.
In the light of the above statements, choose the most appropriate answer from the options given below: