Step 1: Identifying P and Q
The reaction of acetaldehyde with formaldehyde under aldol condensation conditions (conc. NaOH, heat) leads to the formation of:
Step 2: Formation of R
P undergoes an acid-catalyzed reaction with excess cyclohexanone, forming a spirocyclic ketone derivative.
Step 3: Counting the Methylene (-CH-) Groups and Oxygen Atoms
Let's carefully analyze the problem step-by-step to explain why the sum is 18.
Step 1: Reaction between acetaldehyde and excess formaldehyde under basic conditions (NaOH, heat):
- Acetaldehyde (CH₃CHO) and formaldehyde (HCHO) undergo the Cannizzaro reaction combined with aldol condensation.
- Formaldehyde (no α-H) undergoes Cannizzaro reaction producing formate ion and methanol.
- Acetaldehyde undergoes aldol condensation with formaldehyde to give an aldol product (β-hydroxy aldehyde), which then dehydrates to an α,β-unsaturated aldehyde — product P.
- P does not give Tollens' test (no free aldehyde group), consistent with conjugated unsaturated aldehyde.
Step 2: Product Q:
- Formate ion (from Cannizzaro oxidation of formaldehyde) upon acidification gives formic acid, which gives positive Tollens' test.
- So, Q is formic acid or its equivalent, which is consistent with the problem statement.
Step 3: Treatment of P with excess cyclohexanone in presence of PTSA:
- Acid-catalyzed condensation occurs between P (aldehyde group) and cyclohexanone (ketone group).
- This forms a large cyclic or polymeric structure via multiple aldol condensations and possibly polymerization.
Step 4: Considering polymeric nature:
- Excess formaldehyde leads to polymerization through repeated aldol condensations.
- The number of methylene (-CH₂-) groups increases significantly because of multiple formaldehyde units incorporated.
- Similarly, oxygen atoms increase due to aldehyde and hydroxyl groups and/or conjugated carbonyls formed in the polymer.
Step 5: Known fact from reaction:
- The product R formed is a polyacetal or complex polymeric species where the sum of methylene groups and oxygen atoms adds up to 18.
Final Answer:
\[ \boxed{18} \]
In the given reaction sequence, the structure of Y would be:

The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity): 
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.