Question

Choose the most appropriate options. The magnetic moment of M^{x+} (atomic number = 25) is $\sqrt{5}$ BM. Then, the oxidation number x of M is:

• A. 3
• B. 4
• C. 2
• D. 1

Hint:

The magnetic moment can be calculated using the formula $\mu = \sqrt{n(n+2)}$, where $n$ is the number of unpaired electrons.

Answer 1

The Correct Option is B

The magnetic moment $\mu$ for the oxidation state of an element can be calculated using the formula: \[ \mu = \sqrt{n(n+2)} \, {BM} \] where \( n \) is the number of unpaired electrons. For \( \sqrt{5} \) BM, solving for \( n \): \[ \sqrt{n(n+2)} = \sqrt{5} \quad \Rightarrow \quad n(n+2) = 5 \] \[ n^2 + 2n - 5 = 0 \] Solving the quadratic equation gives \( n = 1 \), which corresponds to an oxidation state of \( x = 4 \) for M.