Question:

Choose the most appropriate option. \[ \lim_{x \to 1} \sin(x - 1) \cdot \tan\left( \frac{\pi}{x} \right) \]

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When a term tends to 0 and the other is finite, the product tends to 0.
Updated On: Apr 1, 2025
  • 0
  • \( \frac{1}{\pi} \)
  • \( \frac{2}{\pi} \)
  • \( -\frac{3}{\pi} \)
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The Correct Option is A

Solution and Explanation

As \( x \to 1 \), the term \( \sin(x - 1) \to 0 \) and \( \tan\left( \frac{\pi}{x} \right) \) is finite, so the product of these two terms tends to 0: \[ \lim_{x \to 1} \sin(x - 1) \cdot \tan\left( \frac{\pi}{x} \right) = 0 \]
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