Step 1: Check Right Continuity at \( x = 0 \)
A function \( f(x) \) is right continuous at \( x = a \) if:
\[
\lim_{x \to a^+} f(x) = f(a)
\]
For \( x = 0 \), we check:
\[
\lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} (2 - x) = 2 - 0 = 2
\]
Given that \( f(0) = 0 \), we see:
\[
\lim_{x \to 0^+} f(x) \neq f(0)
\]
Thus, \( f(x) \) is not right continuous at \( x = 0 \), so Option 1 is incorrect.
Step 2: Check Left Continuity at \( x = 1 \)
A function \( f(x) \) is left continuous at \( x = a \) if:
\[
\lim_{x \to a^-} f(x) = f(a)
\]
For \( x = 1 \), we check:
\[
\lim_{x \to 1^-} f(x) = \lim_{x \to 1^-} (2 - x) = 2 - 1 = 1
\]
Since \( f(1) = 2 \), we get:
\[
\lim_{x \to 1^-} f(x) \neq f(1)
\]
Thus, \( f(x) \) is not left continuous at \( x = 1 \), so Option 2 is incorrect.
Step 3: Check Right Continuity at \( x = 1 \)
For right continuity:
\[
\lim_{x \to 1^+} f(x) = \lim_{x \to 1^+} (1 - x) = 1 - 1 = 0
\]
Since \( f(1) = 2 \), we see:
\[
\lim_{x \to 1^+} f(x) \neq f(1)
\]
Thus, \( f(x) \) is not right continuous at \( x = 1 \), so Option 3 is incorrect.
Step 4: Check Continuity at \( x = 2 \)
For continuity at \( x = 2 \), we must check:
\[
\lim_{x \to 2^-} f(x) = f(2) = \lim_{x \to 2^+} f(x)
\]
For \( x \to 2^- \):
\[
\lim_{x \to 2^-} f(x) = \lim_{x \to 2^-} (1 - x) = 1 - 2 = -1
\]
For \( x \geq 2 \), \( f(x) = -\frac{3}{2} \), so:
\[
f(2) = -\frac{3}{2}
\]
Since \( -1 \neq -\frac{3}{2} \), \( f(x) \) is not continuous at \( x = 2 \).
Correction: Answer should be re-evaluated based on proper limits. If needed, provide the correct logical steps for verification.