Choose the correct statements from the following: I) In vapour phase, $ BeCl_2 $ exists as a chlorobridged dimer. II) $ BeSO_4 $ is readily soluble in water. III) $ BeO $ is completely basic in nature. IV) $ BeCO_3 $, being unstable, is kept in the atmosphere of $ CO_2 $. V) $ BeCO_3 $ is less soluble among all the carbonates of group 2 elements.

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Step 1: Checking Statement I - $ BeCl_2 $ in Vapour Phase - $ BeCl_2 $ is covalent and exists as a linear monomer at high temperatures. - However, at lower temperatures, it forms a dimer with $\mu$-chlorine bridging ($ Cl-Be-Cl $ bridge). - Thus, statement I is correct. Step 2: Checking Statement II - Solubility of $ BeSO_4 $ - Beryllium sulfate ($ BeSO_4 $) is highly soluble in water due to its small size and high hydration energy. - Other group 2 sulfates (e.g., $ BaSO_4, SrSO_4 $) are insoluble. - Thus, statement II is correct. Step 3: Checking Statement III - Nature of $ BeO $ - $ BeO $ is amphoteric, meaning it behaves as both an acid and a base. - It dissolves in acids forming $ Be^{2+} $, and in bases forming beryllate ion $ Be(OH)_4^{2-} $. - Since it is not purely basic, statement III is incorrect. Step 4: Checking Statement IV - Stability of $ BeCO_3 $ - $ BeCO_3 $ is highly unstable and decomposes into $ BeO $ and $ CO_2 $. - It is usually stored in $ CO_2 $ atmosphere to prevent decomposition. - Thus, statement IV is correct. Step 5: Checking Statement V - Solubility of $ BeCO_3 $ - Among group 2 carbonates, beryllium carbonate is more soluble than MgCO$_3$, CaCO$_3$, etc. due to its small size and high hydration energy. - Thus, statement V is incorrect. Step 6: Choosing the Correct Option - Correct statements: I, II, IV. - The correct answer is option (2) I, II, IV. \bigskip

Answer

II, III, IV

Answer

Answer

Answer

II, III, V
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The Correct Option is B

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