SnCl\textsubscript{2} is less covalent than SnCl\textsubscript{4}
LiF is more covalent than KF
ZnCl\textsubscript{2} is less covalent than NaCl
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The Correct Option isC
Solution and Explanation
According to Fajan’s rule, smaller cation + larger anion → more covalent character.
Li\textsuperscript{+} is smaller than K\textsuperscript{+}, so LiF has more covalent character than KF.
Other statements are incorrect based on oxidation states and ionic sizes.
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