Write chemical reactions involved in Cannizzaro Reaction of Methanal
The Cannizzaro reaction is a classic redox process where non-enolizable aldehydes, which lack an \(\alpha\)-hydrogen, are treated with a strong base (\(\text{NaOH}\)) to undergo disproportionation. This reaction results in the simultaneous formation of an alcohol and a carboxylate salt.
Consider the reaction with methanal (formaldehyde): \[ 2\text{HCHO} + \text{NaOH} \rightarrow \text{HCOO}^- \text{Na}^+ + \text{CH}_3\text{OH} \]
Identify A in the following reaction. 
For the reaction, \(N_{2}O_{4} \rightleftharpoons 2NO_{2}\) graph is plotted as shown below. Identify correct statements.
A. Standard free energy change for the reaction is 5.40 kJ \(mol^{-1}\).
B. As \(\Delta G\) in graph is positive, \(N_{2}O_{4}\) will not dissociate into \(NO_{2}\) at all.
C. Reverse reaction will go to completion.
D. When 1 mole of \(N_{2}O_{4}\) changes into equilibrium mixture, value of \(\Delta G = -0.84 \text{ kJ mol}^{-1}\).
E. When 2 mole of \(NO_{2}\) changes into equilibrium mixture, \(\Delta G\) for equilibrium mixture is \(-6.24 \text{ kJ mol}^{-1}\).
Choose the correct answer from the following.
