Question:

Calculate the overall complex dissociation equilibrium constant for the $[Cu(NH_3)_4]^{2+}$ ions, given that stability constant ($\beta$) for this complex is $2.1 \times 10^{13}$.

Updated On: Jul 28, 2022
  • $8.27 \times 10^{-13}$
  • $4.76 \times 10^{-14}$
  • $2.39 \times 10^{-7}$
  • $1.83 \times 10^{14}$
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The Correct Option is B

Solution and Explanation

Dissociation constant is the reciprocal of the stability constant ($\beta$ = 1/K). Overall complex dissociation equilibrium constant, $K = \frac{1}{\beta_{4}}$ $\quad\quad\quad=\frac{1}{2.1\times10^{13}}=4.76\times10^{-14}$
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.