Question:
Calcium carbide reacts with heavy water (D$_2$O) to form a compound $ X $ and Ca(OD)$_2$. What is the hybridization of carbon atom(s) in $ X $?
Calcium carbide reacts with heavy water (D$_2$O) to form a compound $ X $ and Ca(OD)$_2$. What is the hybridization of carbon atom(s) in $ X $?
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Triple bonded carbon atoms (like in acetylene) are always \( sp \)-hybridized.
Updated On: May 20, 2025
- \( sp^2 \)
- \( sp \)
- \( sp^3 \)
- \( dsp^2 \)
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The Correct Option is B
Solution and Explanation
Calcium carbide (CaC\(_2\)) reacts with water (or D\(_2\)O) to give acetylene (ethyne or C\(_2\)H\(_2\)) or its deuterated form (C\(_2\)D\(_2\)):
\[
\text{CaC}_2 + 2\text{D}_2\text{O} \rightarrow \text{C}_2\text{D}_2 + \text{Ca(OD)}_2
\]
In C\(_2\)D\(_2\), the carbon atoms are:
- Bonded via a triple bond
- Each bonded to one hydrogen (or deuterium) atom
Hybridization of carbon in a triple bond = \( sp \)
- Bonded via a triple bond
- Each bonded to one hydrogen (or deuterium) atom
Hybridization of carbon in a triple bond = \( sp \)
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