Question

Bromomethane on reaction with Na and dry ether gives:

• A. n-propane
• B. n-butane
• C. isopropane
• D.

Hint:

In the Wurtz reaction, two molecules of an alkyl halide react with sodium to form a larger alkane. Always check the structure of the reactants before determining the product.

Answer 1

The Correct Option is A

Bromomethane (CH\(_3\)Br) undergoes a reaction with sodium metal in dry ether, which is a Wurtz reaction. The Wurtz reaction is a coupling reaction where two alkyl halides react in the presence of sodium to form alkanes. For the reaction of bromomethane with sodium: \[ 2 \, \text{CH}_3\text{Br} + 2 \, \text{Na} \xrightarrow{\text{dry ether}} \text{C}_3\text{H}_8 \quad (\text{n-propane}) \]
Thus, the product formed is n-propane, so the correct answer is \( \text{n-propane} \).