The bond angle decreases as the electronegativity of the element M in \(H_2M\) decreases. It is minimum for \(H_2Te\). The bond angles of \(H_2O, H_2S, H_2Se, H_2Te\) are \(104.5^{\circ}, 92.5^{\circ},91^{\circ}, 90^{\circ}\) respectively.
Bond angle is minimum for H2Te.
The above-mentioned elements are the hydrides of the 6th group elements in which the central atom undergoes SP3 hybridization and should possess a bond angle of 109 degrees. However, the bond angle distorts as a result of the repulsion between the lone pair and the lone pair. But these repulsions are minimum in H2Te as the tellurium has a large size which makes the repulsions minimum.
Therefore, the correct answer is option D, the Bond angle of hydrides decreases down the group.
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.