Question:

Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head on and elastic in nature. After the collision the fraction of energy lost by the colliding body A is :

Updated On: May 25, 2022
  • $\frac{4}{9}$
  • $\frac{5}{9}$
  • $\frac{1}{9}$
  • $\frac{8}{9}$
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The Correct Option is D

Solution and Explanation

Fractional loss of KE of ccolliding body
$\frac{\Delta KE}{KE} = \frac{4\left(m_{1}m_{2}\right)}{\left(m_{1} + m_{2}\right)^{2}} $
$ = \frac{4\left(4m\right)2m}{\left(4m+2m\right)^{2}} $
$ = \frac{32m^{2} }{36m^{2}} = \frac{8}{9} $
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