Question:
Beats are produced by frequencies \( \nu_1 \) and \( \nu_2 \) (\( \nu_1>\nu_2 \)). The duration of time between two successive minima is
Beats are produced by frequencies \( \nu_1 \) and \( \nu_2 \) (\( \nu_1>\nu_2 \)). The duration of time between two successive minima is
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In beat frequency problems, the time period between minima is the reciprocal of the difference between the frequencies.
Updated On: May 15, 2025
- \( \frac{1}{\nu_1 + \nu_2} \)
- \( \frac{2}{\nu_1 - \nu_2} \)
- \( \frac{2}{\nu_1 + \nu_2} \)
- \( \frac{1}{\nu_1 - \nu_2} \)
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The Correct Option is D
Solution and Explanation
The time between two successive minima in a beat is given by the formula:
\[
T = \frac{1}{\nu_1 - \nu_2}
\]
Where \( \nu_1 \) and \( \nu_2 \) are the frequencies producing the beats.
Thus, the correct expression is:
\[
\boxed{T = \frac{1}{\nu_1 - \nu_2}}
\]
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