Question:

Based on data provided, the value of electron gain enthalpy of fluorine would be :

Updated On: Jan 30, 2025
  • $- 300 \, kJ \, mol^{-1}$
  • $- 350 \, kJ \, mol^{-1}$
  • $- 328 \, kJ \, mol^{-1}$
  • $- 228 \, kJ \, mol^{-1}$
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The Correct Option is C

Solution and Explanation

Applying Hess's Law $\Delta_{f} H^{\circ}=\Delta_{\text {sub }} H+\frac{1}{2} \Delta_{\text {diss }} H+I . E+E . A+\Delta_{\text {lattice }} H$ $-617=161+520+77+$ E.A. $+(-1047)$ E. $A .=-617+289=-328 \,kJ \,mol ^{-1}$ $\therefore$ electron affinity of fluorine $=-328\, kJ\, mol ^{-1}$
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: