Question:

Ba-122 has half-life of 2 min. Experiment has to be done using Ba-122 and it takes 10 min to set up the experiment. It initially had 80 g of Ba-122. How much Ba-122 was left when the experiment started?

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Use the formula \( m = m_0 \cdot \left( \frac{1}{2} \right)^n \) for radioactive decay after \( n \) half-lives.
Updated On: Apr 23, 2025
  • 2.5 g
  • 5 g
  • 10 g
  • 20 g
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The Correct Option is A

Solution and Explanation

Given: - Initial mass = 80 g
- Half-life \( t_{1/2} = 2 \) min
- Time elapsed = 10 min
- Number of half-lives = \( \frac{10}{2} = 5 \) After \( n \) half-lives: \[ \text{Remaining mass} = \frac{80}{2^5} = \frac{80}{32} = 2.5 \, \text{g} \]
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