Question

At steady state, the charge on the capacitor, as shown in the circuit below, is -----\( \mu C \). \includegraphics[]{48.PNG}

Hint:

At steady state, a capacitor acts like an open circuit in a DC circuit, and the charge on the capacitor can be calculated using \( Q = C \cdot V \).

Answer 1

Correct Answer: 16

At steady state, the capacitor behaves like an open circuit in a DC circuit. The voltage across the capacitor will be equal to the voltage across the battery, and the charge \( Q \) on the capacitor is given by: \[ Q = C \cdot V, \] where: - \( C \) is the capacitance, - \( V \) is the voltage across the capacitor (which is equal to the battery voltage). Substitute the values for \( C \) and \( V \) to find the charge on the capacitor. The answer is \( 16 \, \mu C \).