Question:

At sea level, the value of $g$ is minimum at

Updated On: Jul 28, 2022
  • the poles
  • the equator
  • $45^{\circ}$ south latitude
  • $45^{\circ}$ north longitude
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The Correct Option is B

Solution and Explanation

Due to the rotation of the earth, the acceleration due to gravity for earth changes and at the equator, its value is given by $ g' = g - w^2 R $ And at poles $g'=g$ $\therefore$ The value of acceleration due to gravity is minimum at the equator.
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].