Question:

The gravitational potential at a point above the surface of earth is \( -5.12 \times 10^7 \, \text{J} / \text{kg} \) and the acceleration due to gravity at that point is \( 6.4 \, \text{m/s}^2 \). Assume that the mean radius of earth to be \( 6400 \, \text{km} \). The height of this point above the earth’s surface is:

Updated On: Nov 11, 2024
  • 1200 km
  • 540 km
  • 1600 km
  • 1000 km
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The Correct Option is C

Solution and Explanation

Using the formula for gravitational potential and gravitational field:

\(\frac{-G M_E}{R_E + h} = -5.12 \times 10^7\)    and    \(\frac{G M_E}{(R_E + h)^2} = 6.4\)

\(16 \times 10^5\)

(This is in meters)

To convert, divide by 1000:

\(h = 1600 \, \text{km}\)

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Concepts Used:

Units and Measurement

Unit:

A unit of a physical quantity is an arbitrarily chosen standard that is broadly acknowledged by the society and in terms of which other quantities of similar nature may be measured.

Measurement:

The process of measurement is basically a comparison process. To measure a physical quantity, we have to find out how many times a standard amount of that physical quantity is present in the quantity being measured. The number thus obtained is known as the magnitude and the standard chosen is called the unit of the physical quantity.

Read More: Fundamental and Derived Units of Measurement

System of Units:

  1. CGS system
  2. FPS system
  3. MKS system
  4. SI units

Types of Units:

Fundamental Units -

The units defined for the fundamental quantities are called fundamental units.

Derived Units -

The units of all other physical quantities which are derived from the fundamental units are called the derived units.