At constant temperature, the internal energy of a Van der Waals gas:
Show Hint
- Remains constant
- Is proportional to volume \( V \) of the gas
- Is inversely proportional to the volume \( V \) of the gas
- Is independent of volume of the gas
The Correct Option is D
Solution and Explanation
\[ U = U(T) \] At constant temperature, the internal energy remains independent of volume.
Top Questions on Thermodynamics
- In adiabatic compression, which of the following is true?
- MHT CET - 2025
- Physics
- Thermodynamics
1.24 g of $ {AX}_2 $ (molar mass 124 g mol$^{-1}$) is dissolved in 1 kg of water to form a solution with boiling point of 100.105$^\circ$C, while 2.54 g of $ {AY}_2 $ (molar mass 250 g mol$^{-1}$) in 2 kg of water constitutes a solution with a boiling point of 100.026$^\circ$C. $ K_{b(H_2O)} = 0.52 \, \text{K kg mol}^{-1} $. Which of the following is correct?
- JEE Main - 2025
- Chemistry
- Thermodynamics
An amount of ice of mass \( 10^{-3} \) kg and temperature \( -10^\circ C \) is transformed to vapor of temperature \( 110^\circ C \) by applying heat. The total amount of work required for this conversion is,
(Take, specific heat of ice = 2100 J kg\(^{-1}\) K\(^{-1}\),
specific heat of water = 4180 J kg\(^{-1}\) K\(^{-1}\),
specific heat of steam = 1920 J kg\(^{-1}\) K\(^{-1}\),
Latent heat of ice = \( 3.35 \times 10^5 \) J kg\(^{-1}\),
Latent heat of steam = \( 2.25 \times 10^6 \) J kg\(^{-1}\))- JEE Main - 2025
- Physics
- Thermodynamics
- Consider ‘n’ is the number of lone pair of electrons present in the equatorial position of the most stable structure of \( \text{ClF}_3 \). The ions from the following with ‘n’ number of unpaired electrons are:
A. \( \text{V}^{3+} \)
B. \( \text{Ti}^{3+} \)
C. \( \text{Cu}^{2+} \)
D. \( \text{Ni}^{2+} \)
E. \( \text{Ti}^{2+} \)
Choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- Thermodynamics
- What is the freezing point depression constant of a solvent, 50 g of which contain 1 g non-volatile solute (molar mass 256 g mol\(^{-1}\)) and the decrease in freezing point is 0.40 K?
- JEE Main - 2025
- Chemistry
- Thermodynamics
Questions Asked in BHU PET exam
- Given the Bessel function:
$$ J_0(x) = 1 - \frac{x^2}{2^2} + \frac{x^4}{2^2 \cdot 2^2} - \frac{x^6}{2^2 \cdot 2^2 \cdot 2^2} + \dots $$ The Bessel function $ J_1(x) $ is given by:- BHU PET - 2019
- Special Functions
- One solution (about $ x = 0 $ ) of the differential equation
$$ x^2 \frac{d^2 y}{dx^2} - 3x \frac{dy}{dx} + 4y = 0 $$ is $ y_1(x) = c_1x^2$ . A second linearly independent solution (with another constant $ c_2 $ ) is:- BHU PET - 2019
- Differential Equations
- What will be the change in the volume of a cube when its side becomes 10 times the original side?
- BHU PET - 2019
- Volume of Cube, Cuboid and Cylinder
- In how many ways can the letters of the word 'PERMUTATIONS' be arranged if vowels are together?
- BHU PET - 2019
- Permutations and Combinations
- The number of diagonals that can be drawn by joining the vertices of an octagon is:
- BHU PET - 2019
- Geometry