At any instant \( t \), the vertical distance \( Y \) and horizontal distance \( X \) of a projectile are given by
\[
2Y = 6t - g t^2 \quad \text{and} \quad X = 4t,
\]
The initial velocity of the projectile is:
Show Hint
In projectile motion, the initial velocity can be found by analyzing the horizontal and vertical motion equations.
By comparing the given equations for vertical and horizontal motion of the projectile, we can calculate the initial velocity using the standard equations for projectile motion. The initial velocity is determined to be 5 m/s.
Thus, the correct answer is option (3).