frequency of heterozygotes (Aa) using the formula:
Frequency of heterozygotes (Aa) = 2 \(\times\) Frequency of 'A' allele (p) \(\times\) Frequency of 'a' allele (q)
Given:
Frequency of 'A' allele (p) = 0.6
Frequency of 'a' allele (q) = 0.4
Frequency of heterozygotes (Aa) = 2 \(\times\) 0.6 \(\times\) 0.4 = 0.48
So, the frequency of heterozygotes in a random mating population at equilibrium is 0.48.
Therefore, the correct answer is (B): 0.48
The given graph shows the range of variation among population members, for a trait determined by multiple genes. If this population is subjected to disruptive selection for several generations, which of the following distributions is most likely to result?
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec:
In a considerable size, random-mating population, the genotype and allele frequencies remain constant in the absence of any evolutionary influences from one generation to another. Influences include a choice of mate, natural selection, genetic drift, mutation, sexual selection, gene flow, genetic hitchhiking, founder effect, meiotic drive, population bottleneck, inbreeding, and assortative mating.
Following are a few assumptions for the law: