Question:
At a certain time a particle has a speed of $18\, m/s$ in positive x-direction and $2.4\, s$ later its speed was $30\, m/s$ in the opposite direction. What is the magnitude of the average acceleration of the particle during the $2.4\, s$ interval?
At a certain time a particle has a speed of $18\, m/s$ in positive x-direction and $2.4\, s$ later its speed was $30\, m/s$ in the opposite direction. What is the magnitude of the average acceleration of the particle during the $2.4\, s$ interval?
Updated On: Jun 14, 2022
- $ 20\,m/s^{2}$
- $ 10\,m/s^{2}$
- $ 5\,m/s^{2}$
- $ 2.5\,m/s^{2}$
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The Correct Option is A
Solution and Explanation
Average acceleration $=\frac{\text { change in veloclty }}{\text { Time taken }}$
$=\frac{-30\, m / s -18\, m / s }{2.4}=20\, m / s ^{2}$
$=\frac{-30\, m / s -18\, m / s }{2.4}=20\, m / s ^{2}$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.